Question

1)3(x-2)=33 2)-2(x+4)=10-4x 3)-4(x-2)-(5-3x)=14+(5-9x)

Answer 1

Ответ:

1) 3x-6=33

3x=33+6

x=39:3

x=13

2) -2x-8=10-4x

-2x+4x=10+8

2x=18

x=18:2

x=9

3) -4x+8-5+3x=14+5-9x

-4x+3x+9x=14+5-8+5

8x=16

x=16:8

x=2

Answer 2

Sure, I'd be happy to help you solve these equations. Let's go through them one by one:

1. $3(x-2) = 33$

First, distribute the 3 on the left side:

$3x - 6 = 33$

Next, isolate $x$ by adding 6 to both sides:

$3x = 39$

Finally, divide both sides by 3 to solve for $x$:

$x = 13$

So, the solution to the first equation is $x = 13$.

2. $-2(x+4) = 10 - 4x$

First, distribute the -2 on the left side:

$-2x - 8 = 10 - 4x$

Next, add $2x$ to both sides:

$-8 = 10 - 2x$

Then, subtract 10 from both sides:

$-18 = -2x$

Finally, divide both sides by -2 to solve for $x$:

$x = 9$

So, the solution to the second equation is $x = 9$.

3. $-4(x-2) - (5 - 3x) = 14 + (5 - 9x)$

First, distribute the -4 on the left side and the -1 on the right side:

$-4x + 8 - 5 + 3x = 14 + 5 - 9x$

Simplify both sides:

$-x + 3 = 19 - 9x$

Next, add $9x$ to both sides:

$8x + 3 = 19$

Then, subtract 3 from both sides:

$8x = 16$

Finally, divide both sides by 8 to solve for $x$:

$x = 2$

So, the solution to the third equation is $x = 2$.