Question

А) (1 3/5+2 1/5) ÷ 1 9/10 +(1 7/10-4/3) ÷3-3/7=б) 6 3/8 × 1 1/17- 2 3/8÷1 1/4+2/5​

Answer 1

а) (1 3/5 + 2 1/5) : 1 9/10 + (1 7/10 - 4/3) : 3 3/7 = 2 77/720

1) 1 3/5 + 2 1/5 = 3 4/5

2) 1 7/10 = 4/3 = 17/10 - 4/3 = 51/30 - 40/30 = 11/30

3) 3 4/5 : 1 9/10 = 19/5 : 19/10 = 19/5 · 10/19 = 10/5 = 2

4) 11/30 : 3 3/7 = 11/30 : 24/7 = 11/30 · 7/24 = 77/720

5) 2 + 77/720 = 2 целых 77/720.

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б) 6 3/8 · 1 1/17 - 2 3/8 : 1 1/4 + 2/5 = 5 1/4

1) 6 3/8 · 1 1/17 = 51/8 · 18/17 = (3·9)/(4·1) = 27/4 = 6 3/4

2) 2 3/8 : 1 1/4 = 19/8 : 5/4 = 19/8 · 4/5 = (19·1)/(2·5) = 19/10 = 1 9/10

3) 6 3/4 - 1 9/10 = 6 15/20 - 1 18/20 = 5 35/20 - 1 18/20 = 4 17/20

4) 4 17/20 + 2/5 = 4 17/20 + 8/20 = 4 25/20 = 4 5/4 = 5 целых 1/4

Answer 2

Let's break down and simplify each expression:

а)

$$\begin{align*} &(1\frac{3}{5} + 2\frac{1}{5}) ÷ 1\frac{9}{10} + \left(1\frac{7}{10} - \frac{4}{3}\right) ÷ 3 - \frac{3}{7} \\ =& \left(\frac{8}{5} + \frac{11}{5}\right) ÷ \frac{19}{10} + \left(\frac{17}{10} - \frac{4}{3}\right) ÷ 3 - \frac{3}{7} \\ =& \frac{19}{5} ÷ \frac{19}{10} + \frac{51}{30} ÷ 3 - \frac{3}{7} \\ =& \frac{19}{5} × \frac{10}{19} + \frac{51}{30} ÷ 3 - \frac{3}{7} \\ =& 2 + \frac{51}{90} - \frac{3}{7} \\ =& 2 + \frac{17}{30} - \frac{3}{7} \\ =& \frac{60}{30} + \frac{17}{30} - \frac{90}{30} \\ =& \frac{60 + 17 - 90}{30} \\ =& \frac{-13}{30} \end{align*}$$

б)

$$\begin{align*} &6\frac{3}{8} × 1\frac{1}{17} - 2\frac{3}{8} ÷ 1\frac{1}{4} + \frac{2}{5} \\ =& \frac{51}{8} × \frac{18}{17} - \frac{19}{8} ÷ \frac{5}{4} + \frac{2}{5} \\ =& \frac{459}{17} - \frac{38}{5} + \frac{2}{5} \\ =& \frac{459}{17} - \frac{38 + 2}{5} \\ =& \frac{459}{17} - \frac{40}{5} \\ =& \frac{459 - 136}{17} \\ =& \frac{323}{17} \\ =& 18\frac{7}{17} \end{align*}$$

So, the values are: а) $\frac{-13}{30}$ б) $18\frac{7}{17}$