Question

(2, 7 - 2 1/3)(- 4 2/7) + 8 3/4 / (- 3, 5) С решениям пжпж У МЕНЯ СОР​

Answer 1

Ответ:

$15\frac{13}{14}$

Пошаговое объяснение:

$(2,7-7)*(-\frac{30}{7} )+\frac{35}{4} /(-\frac{7}{2} )=\\-4,3*(-\frac{30}{7} )-\frac{35}{4} *\frac{2}{7} =\\-\frac{43}{10} *(-\frac{30}{7} )-\frac{5}{2} =\\43*\frac{3}{7} -\frac{5}{2} =\frac{129}{7} -\frac{5}{2} =\\\frac{223}{14} =15\frac{13}{14}$

Answer 2

To solve the given expression, let's break it down step by step using the order of operations (PEMDAS: Parentheses, Exponents, Multiplication and Division, Addition and Subtraction).

Expression: (2, 7 - 2 1/3) * (- 4 2/7) + 8 3/4 / (- 3, 5)

First, let's simplify within the parentheses:

1. $7 - 2 \frac{1}{3}$: $7 - 2 \frac{1}{3} = \frac{21}{3} - \frac{7}{3} - \frac{1}{3} = \frac{13}{3}$

Now, the expression becomes:

$\left(2, \frac{13}{3}\right) \times \left(- 4 \frac{2}{7}\right) + \frac{8 \frac{3}{4}}{- 3, 5}$

Next, let's deal with the multiplication:

2. $\left(2, \frac{13}{3}\right) \times \left(- 4 \frac{2}{7}\right)$: To multiply mixed numbers, convert them to improper fractions: $2 + \frac{13}{3} = \frac{6}{3} + \frac{13}{3} = \frac{19}{3}$ $- 4 \frac{2}{7} = - \frac{30}{7} - \frac{2}{7} = - \frac{32}{7}$ Now, multiply: $\frac{19}{3} \times - \frac{32}{7} = - \frac{608}{21}$

The expression now becomes:

$- \frac{608}{21} + \frac{8 \frac{3}{4}}{- 3, 5}$

Next, let's deal with the division:

3. $\frac{8 \frac{3}{4}}{- 3, 5}$: Convert the mixed number to an improper fraction: $8 \frac{3}{4} = \frac{8 \times 4 + 3}{4} = \frac{35}{4}$ Now, divide: $\frac{35}{4} \div - \frac{3}{5} = \frac{35}{4} \times - \frac{5}{3}$ Simplify: $\frac{35}{4} \times - \frac{5}{3} = - \frac{175}{12}$

The expression now becomes:

$- \frac{608}{21} + - \frac{175}{12}$

Finally, let's perform addition:

4. $- \frac{608}{21} + - \frac{175}{12}$: To add these fractions, we need a common denominator. The least common multiple of 21 and 12 is 84. Rewrite the fractions with the common denominator: $- \frac{608 \times 4}{21 \times 4} + - \frac{175 \times 7}{12 \times 7}$ $- \frac{2432}{84} + - \frac{1225}{84}$

Now, add the fractions:

$-\frac{2432+1225}{84}=-\frac{3657}{84}$ 0 0