Question

7(5f+30)+6(25-3f)=411​

Answer 1

35f+210+150-18f=411
17f=411-360
17f=51
f=3

Answer 2

To solve for the value of 'f' in the equation 7(5f+30)+6(25-3f)=411, you can follow these steps:

1. Distribute the constants on the left side of the equation:

7 * 5f + 7 * 30 + 6 * 25 - 6 * 3f = 411

2. Simplify by performing the multiplications:

35f + 210 + 150 - 18f = 411

3. Combine like terms:

(35f - 18f) + (210 + 150) = 411

17f + 360 = 411

4. Isolate 'f' by moving the constant term (360) to the other side of the equation by subtracting it from both sides:

17f = 411 - 360

17f = 51

5. Now, divide both sides by 17 to solve for 'f':

f = 51 / 17

f = 3

So, the solution to the equation is f = 3.