Question

1)^5√(^10√2)^2-^3√135+^3√1080 2)^3√-81+^3√24+√18-^4√(-2)^2 3)^5√192-√48-^4√(-3)^2-2^5√-964)^5√-486+√245+^5√(-2)^6+√45

Answer 1

Ответ:Господи это вообще какой класс...

Пошаговое объяснение:

Answer 2

Let's simplify each of these expressions step by step:

1. $5\sqrt{\left(10\sqrt{2}\right)^2} - \sqrt[3]{135} + \sqrt[3]{1080}$

First, calculate the innermost expressions:

• $\left(10\sqrt{2}\right)^2 = 100 \cdot 2 = 200$
• $\sqrt[3]{135} = 5$
• $\sqrt[3]{1080} = 6$

Now, substitute these values back into the main expression:

$5\sqrt{200} - 5 + 6$

Next, simplify the square root:

$5\sqrt{200} = 5\sqrt{100 \cdot 2} = 5 \cdot 10 \sqrt{2} = 50\sqrt{2}$

So the expression becomes:

$50\sqrt{2} - 5 + 6$

Now, combine like terms:

$50\sqrt{2} + 1$

2. $\sqrt[3]{-81} + \sqrt[3]{24} + \sqrt{18} - \sqrt[4]{(-2)^2}$

Let's start by simplifying the cube roots and square root:

• $\sqrt[3]{-81} = -4$ (because $-4 \times -4 \times -4 = -64$)
• $\sqrt[3]{24} = 2$
• $\sqrt{18} = \sqrt{9 \cdot 2} = 3\sqrt{2}$
• $\sqrt[4]{(-2)^2} = \sqrt[4]{4} = 2$ (since the fourth root of 4 is 2)

Now, substitute these values back into the main expression:

$-4 + 2 + 3\sqrt{2} - 2$

Now, combine like terms:

$-4 + 2 - 2 + 3\sqrt{2} = -4 + 3\sqrt{2}$

3. $5\sqrt{192} - \sqrt{48} - \sqrt[4]{(-3)^2} - 2^5\sqrt{-96}$