
-4•(6-8)+4-3x=???


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Пошаговое объяснение:
какой класс скажи???? алооо



To solve this equation, you can follow the order of operations (PEMDAS/BODMAS), which stands for Parentheses/Brackets, Exponents/Orders (i.e., powers and square roots, etc.), Multiplication and Division (left-to-right), and Addition and Subtraction (left-to-right). Let's solve it step by step:
Equation: -4(6 - 8) + 4 - 3x
Start with the parentheses: -4(6 - 8) = -4(-2)
Now, perform the multiplication inside the parentheses: -4(-2) = 8
Next, simplify the addition and subtraction from left to right: 8 + 4 = 12
Your equation now looks like this: 12 - 3x
So, the simplified equation is: 12 - 3x
If you want to solve for 'x,' you can isolate 'x' on one side of the equation. Here's how:
Start with the equation: 12 - 3x = ???
To isolate 'x,' first, subtract 12 from both sides of the equation to move the constant to the other side: 12 - 3x - 12 = ??? - 12 -3x = ??? - 12
You can leave the right side as it is if you have specific values for the question marks. If not, you can keep it as "-12" or any other variable.
Finally, to solve for 'x,' divide both sides by -3: (-3x) / (-3) = (-12) / (-3) x = 4
So, the solution for the equation -4(6 - 8) + 4 - 3x is x = 4, assuming you have specific values for the question marks on the right side.


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