Question

А) 4y-3 (20-y)=6y-7(11-y)-1

Answer 1

Ответ:

4y-3 (20-y)=6y-7(11-y)-1

4у-60+3у = 6у-77+7у-1

4у+3у-6у-7у = -77-1+60

-6у = -18

у= -18 / -6

у= 3

Ответ 3

Пошаговое объяснение:

Answer 2

Let's solve the equation step by step:

1. Start by distributing the terms on both sides of the equation:

4y - 3(20 - y) = 6y - 7(11 - y) - 1

2. Simplify the expressions inside the parentheses:

4y - (3 * 20) + 3y = 6y - (7 * 11) + 7y - 1

3. Perform the multiplications and simplifications:

4y - 60 + 3y = 6y - 77 + 7y - 1

4. Combine like terms on each side of the equation:

(4y + 3y) - 60 = (6y + 7y) - 77 - 1

7y - 60 = 13y - 78

5. Move the variables to one side and constants to the other side by adding 60 and subtracting 13y from both sides:

7y - 13y = -78 + 60

-6y = -18

6. Finally, solve for y by dividing both sides by -6:

y = (-18) / (-6)

y = 3

So, the solution to the equation is y = 3.