Question

1.sederhanakan bentuk akar di bawah: a. √108b.√448c.√405d.√432e.√3362.hitunglah nilai dari:a.3√5 + 4√5b.2√7 - 3√7 - 4√7c.√32 - √18 + √8d.√125 - √45 √20e.10√12 - 2√27 - √75 ​

Answer 1

Ответ:

Пошаговое объяснение:

a. √108 = $\sqrt{36*3}$=$\sqrt{6^{2}*3 }$ =6$\sqrt{3}$

b.√448= $\sqrt{64*7}$= $\sqrt{8^{2}*7 }$=8$\sqrt{7}$

c.√405= $\sqrt{81*5}$=$\sqrt{9^{2}*5 }$ =9$\sqrt{5}$

d.√432=$\sqrt{144*3}$=$\sqrt{12^{2}*3 }$=12$\sqrt{3}$

e.√336=$\sqrt{16*21}$=$\sqrt{4^{2}*21 }$=4$\sqrt{21}$

2.hitunglah nilai dari:

a.3√5 + 4√5 = $\sqrt{5}$(3+4)=7$\sqrt{5}$

b.2√7 - 3√7 - 4√7 = $\sqrt{7}$(2-3-4)=-5$\sqrt{7}$

c.√32 - √18 + √8 = $\sqrt{16*2}$- $\sqrt{9*2}$ + $\sqrt{4*2}$ = $\sqrt{4^{2}*2 }$ - $\sqrt{3^{2} *2}$ + $\sqrt{2^{2}*2 }$

=4$\sqrt{2}$ - 3$\sqrt{2}$ +2$\sqrt{2}$ = $\sqrt{2}$ (4-3+2)=3$\sqrt{2}$

d.√125 - √45 - √20 = $\sqrt{25*5}$ - $\sqrt{9*5}$ - $\sqrt{4*5}$ = $\sqrt{5^{2}*5 }$ - $\sqrt{3^{2}*5 }$ - $\sqrt{2^{2}*5 }$ =

= 5$\sqrt{5}$ - 3$\sqrt{5}$ -2 $\sqrt{5}$ = $\sqrt{5}$ (5-3-2) =$\sqrt{5}$ *0=0

e.10√12 - 2√27 - √75 ​= 10$\sqrt{4*3}$ - 2 $\sqrt{9*3}$ - $\sqrt{25*3}$ = 10$\sqrt{2^{2} *3}$ - 2$\sqrt{3^{2}*3 }$ - $\sqrt{5^{2}*3 }$ = 10*2$\sqrt{3}$ - 2*3$\sqrt{3}$ - 5$\sqrt{3}$ = $\sqrt{3}$ (10*2 - 2*3 -5)= $\sqrt{3}$ (20-6-5)=9$\sqrt{3}$

Answer 2

1. Sederhanakan bentuk akar di bawah: a. √108 = √(36 * 3) = 6√3 b. √448 = √(64 * 7) = 8√7 c. √405 = √(81 * 5) = 9√5 d. √432 = √(144 * 3) = 12√3 e. √336 = √(16 * 21) = 4√21

2. Hitunglah nilai dari: a. 3√5 + 4√5 = 7√5 b. 2√7 - 3√7 - 4√7 = (2 - 3 - 4)√7 = -5√7 c. √32 - √18 + √8 = (4√2 - 3√2 + 2√2) = 3√2 d. √125 - √45 √20 = (5√5 - 3√5 * 2√5) = (5√5 - 6√5) = -√5 e. 10√12 - 2√27 - √75 = (10 * 2√3 - 2 * 3√3 - 5√3) = (20√3 - 6√3 - 5√3) = 9√3