Question

1)5/19+7/19-4/192)7 5/7+6/73)1-9/134)9 7/13-6 9/13​

Answer 1

Ответ:

1)5+7-4/19=8/19

2)54/7+6/7=60/7

3)13-9/13=4/13

4)124/13-87/13=37/13

Answer 2

Let's solve each of these arithmetic problems step by step:

1. $\frac{5}{19} + \frac{7}{19} - \frac{4}{19}$ First, find a common denominator, which in this case is 19. $\frac{5}{19} + \frac{7}{19} - \frac{4}{19} = \frac{5 + 7 - 4}{19} = \frac{8}{19}$

2. $7 \frac{5}{7} + \frac{6}{7}$ To add these fractions, you need to make the whole numbers have the same denominator as the fractions. $7 \frac{5}{7} + \frac{6}{7} = \frac{7 \cdot 7}{7} + \frac{6}{7} = \frac{49}{7} + \frac{6}{7}$ Now, you can add the fractions because they have the same denominator. $\frac{49 + 6}{7} = \frac{55}{7} = 7 \frac{6}{7}$

3. $1 - \frac{9}{13}$ To subtract, you need a common denominator, which is 13 in this case. $1 - \frac{9}{13} = \frac{13}{13} - \frac{9}{13}$ Now, subtract the fractions. $\frac{13 - 9}{13} = \frac{4}{13}$

4. $9 \frac{7}{13} - 6 \frac{9}{13}$ To subtract these mixed numbers, first subtract the whole numbers and then subtract the fractions. $(9 - 6) \frac{7}{13} - \frac{9}{13}$ $3 \frac{7}{13} - \frac{9}{13}$ Now, subtract the fractions. $3 \frac{7 - 9}{13} = 3 \frac{-2}{13}$

So, the answers are:

1. $\frac{8}{19}$
2. $7 \frac{6}{7}$
3. $\frac{4}{13}$
4. $3 \frac{-2}{13}$