Question

-3x(x+1)=0x(-x-2)(x+2)=0​

Answer 1

Ответ:

1) x=0, x= -  1

2) x=0, x= -2

Пошаговое объяснение:

$-3x(x+1)=0\\\\-3x=0\ \ \ |:(-3)\ \ \ \ \ x+1=0\\\\x=0\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x=-1$

$x(-x-2)(x+2)=0\\\\\ x=0\ \ \ \ \ \ -x-2=0\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x+2=0\\\\.\ \ \ \ \ \ \ \ \ \ \ \ -x=2\ \ \ |:(-1)\ \ \ \ \ \ \ \ \ x=-2\\\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ x=-2$

Answer 2

Удачи!!!!!!!!!!!!!!!!!!!

Answer 3

To solve the equation $-3x(x+1) = 0$, we can start by using the zero-product property. The zero-product property states that if $a \cdot b = 0$, then either $a = 0$ or $b = 0$.

In this case, we have:

$-3x(x+1) = 0$

So, either $-3x = 0$ or $x + 1 = 0$.

Solving these separately:

1. $-3x = 0$ Dividing both sides by -3, we get $x = 0$.

2. $x + 1 = 0$ Subtracting 1 from both sides, we get $x = -1$.

Next, for the equation $x(-x-2)(x+2) = 0$, we apply the zero-product property again.

So, either $x = 0$, $-x - 2 = 0$, or $x + 2 = 0$.

Solving these separately:

1. $x = 0$ (already found from the first equation).

2. $-x - 2 = 0$ Adding $x$ to both sides, we get $-2 = x$ or $x = -2$.

3. $x + 2 = 0$ Subtracting 2 from both sides, we get $x = -2$ (which was already found in the second case).

So, the solutions to the equation $x(-x-2)(x+2) = 0$ are $x = 0$, $x = -2$, and $x = -1$.