Question

1)125÷(х+5)=25. 2)(х+55)÷7=19. 3)198÷(х+8)=9. 4)7×(х+11)=105. 5)140-(х÷7+29)×4=12​

Answer 1

Ответ:

Пошаговое объяснение:

x + 5 = 125/25
x + 5 = 5
x = 0
______

x + 55 = 19 * 7
x + 55 = 133
x = 78
______

x + 8 = 198/9
x + 8 = 22
x = 14
______

x + 11 = 105/7
x + 11 = 15
x = 4
______

(x/7 + 29) * 4 = 140 - 12
(x/7 + 29) * 4  = 128
x/7 + 29 = 128/4
x/7 + 29 = 32
x/7 = 32 - 29
x/7 = 3
x = 3 * 7 = 21

Answer 2

Ответ:

1)0

2)78

3)14

4)4

5)не знаю

Пошаговое объяснение:

1)125÷(x+5)=25

x+5=125÷25

x+5=5

x=5-5

x=0

125÷(0+5)=25

25=25

2)(x+55)÷7=19

x+55=19×7

x+55=133

x=133-55

x=78

(78+55)÷7=19

19=19

3)198÷(x+8)=9

x+8=198÷9

x+8=22

x=22-8

x=14

198÷(14+8)=9

9=9

4)7×(x+11)=105

x+11=105÷7

x+11=15

x=15-11

x=4

7×(4+11)=105

105=105

5)не знаю

Когда ми решаем сложное уравнение, то то что в скобках мы закрываем когбуто бы что то x и решаем как обычное уравнение, а когда его решили то ми получаем следующее уравнение но уже простое без скобок и то что получили и есть x.

Answer 3

To solve these equations, we'll isolate the variable $x$ in each equation. Here are the solutions to each of the equations:

1. $125 ÷ (x + 5) = 25$:

   First, multiply both sides of the equation by $(x + 5)$:

   $125 = 25(x + 5)$

   Now, divide both sides by 25 to isolate $x$:

   $5 = x + 5$

   Finally, subtract 5 from both sides to solve for $x$:

   $x = 0$

2. $(x + 55) ÷ 7 = 19$:

   First, multiply both sides of the equation by 7:

   $x + 55 = 7 \cdot 19$

   $x + 55 = 133$

   Now, subtract 55 from both sides to solve for (x:

   $x = 133 - 55$

   $x = 78$

3. $198 ÷ (x + 8) = 9$:

   First, multiply both sides of the equation by $(x + 8)$:

   $198 = 9(x + 8)$

   Now, divide both sides by 9 to isolate $x$:

   $22 = x + 8$

   Finally, subtract 8 from both sides to solve for (x:

   $x = 22 - 8$

   $x = 14$

4. $7(x + 11) = 105$:

   First, distribute the 7 on the left side of the equation:

   $7x + 77 = 105$

   Now, subtract 77 from both sides to solve for (x:

   $7x = 105 - 77$

   $7x = 28$

   Finally, divide both sides by 7:

   $x = 28 ÷ 7$

   $x = 4$

5. $140 - (x ÷ 7 + 29) \cdot 4 = 12$:

   First, simplify the equation by performing the operations inside the parentheses and brackets:

   $140 - (x/7 + 29) \cdot 4 = 12$

   Now, multiply both sides by -1 to make it easier to work with:

   $-140 + (x/7 + 29) \cdot 4 = -12$

   Add 140 to both sides:

   $(x/7 + 29) \cdot 4 = -12 + 140$

   $(x/7 + 29) \cdot 4 = 128$

   Divide both sides by 4:

   $x/7 + 29 = 32$

   Subtract 29 from both sides to isolate $x/7$:

   $x/7 = 32 - 29$

   $x/7 = 3$

   Finally, multiply both sides by 7 to solve for (x:

   $x = 3 \cdot 7$

   $x = 21$

So, the solutions to the equations are:

1. $x = 0$
2. $x = 78$
3. $x = 14$
4. $x = 4$
5. $x = 21$