Question

3(4-с)=6-(8с+3)

Answer 1

3(4-с)=6-(8с+3) 12-3c=6-8c-3 8c-3c=3-12 5c=-9 c=-9:5 c=-1.8

Answer 2

Let's solve the equation for с:

3(4 - с) = 6 - (8с + 3)

First, distribute the 3 on the left side of the equation:

12 - 3с = 6 - (8с + 3)

Now, simplify the right side by removing the parentheses. To do this, distribute the negative sign (-) within the parentheses:

12 - 3с = 6 - 8с - 3

Now, let's group like terms on the right side of the equation:

12 - 3с = (6 - 3) - 8с

Now, simplify further:

12 - 3с = 3 - 8с

Next, let's get all the terms with с on one side of the equation and the constants on the other side. To do this, add 8с to both sides of the equation:

12 - 3с + 8с = 3 - 8с + 8с

This simplifies to:

12 + 5с = 3

Now, subtract 12 from both sides to isolate 5с:

12 + 5с - 12 = 3 - 12

This simplifies to:

5с = -9

Finally, divide both sides by 5 to solve for с:

5с/5 = -9/5

с = -9/5

So, с = -9/5 is the solution to the equation.