Question

1)340*×-416*2=18208 2)(223440-130*×):35=6020 3)(31*550-×)*120=10200

Answer 1

1)340×х-416×2=18208
340×х=18208+832
340×х=19040
х=19040÷340
х=56
340×56-416×2=18208
19040-832=18208
18208=18208
2)(223440-130×х)÷35=6020
223440-130×х=6020×35
130×х=223440-210700
130×х=12740
х=12740÷130
х=98
(223440-130×98)÷35=6020
210700÷35=6020
6020=6020
3)(31×550-х)×120=10200
17050-х=10200÷120
17050-х=85
х=17050-85
х=16965
(31×550-16965)×120=10200
(17050-16965)×120=10200
85×120=10200
10200=10200

Answer 2

It looks like you have three equations with variables denoted by "×." Let's solve each of them step by step:

1. 340 * × - 416 * 2 = 18208:

First, multiply 416 by 2: 416 * 2 = 832

Now, subtract 832 from both sides of the equation to isolate ×: 340 * × - 832 = 18208 - 832

340 * × = 17376

Now, divide both sides by 340 to solve for ×: × = 17376 / 340 × ≈ 51.10588 (rounded to 5 decimal places)

2. (223440 - 130 * ×) / 35 = 6020:

First, multiply 130 by ×: 130 * ×

Now, subtract this result from 223440: 223440 - 130 * ×

Now, we have: (223440 - 130 * ×) / 35 = 6020

To isolate ×, multiply both sides by 35: 223440 - 130 * × = 6020 * 35

223440 - 130 * × = 210700

Now, subtract 223440 from both sides: -130 * × = 210700 - 223440

-130 * × = -12740

Divide both sides by -130 to solve for ×: × = (-12740) / (-130) × ≈ 98.15385 (rounded to 5 decimal places)

3. (31 * 550 - ×) * 120 = 10200:

First, multiply 31 by 550: 31 * 550 = 17050

Now, subtract × from this result: 17050 - ×

Now, we have: (17050 - ×) * 120 = 10200

To isolate ×, divide both sides by 120: (17050 - ×) = 10200 / 120

17050 - × = 85

Now, subtract 17050 from both sides:

• × = 85 - 17050

• × = -16965

Multiply both sides by -1 to solve for ×: × = 16965

So, the solutions to the equations are:

1. × ≈ 51.10588
2. × ≈ 98.15385
3. × = 16965