Question

(17÷3 2/5-6 3/8 3 3/8)÷(1 1/5-29/30)

Answer 1

Ответ _____38,2906462

Answer 2

To solve this expression, we'll follow the order of operations (PEMDAS/BODMAS: Parentheses/Brackets, Exponents/Orders, Multiplication and Division, Addition and Subtraction) and convert all mixed fractions to improper fractions for easier calculations.

Let's break down the expression step by step:

1. Convert mixed fractions to improper fractions:

   • $2 \frac{2}{5} = \frac{5 \times 2 + 2}{5} = \frac{12}{5}$
   • $6 \frac{3}{8} = \frac{8 \times 6 + 3}{8} = \frac{51}{8}$
   • $3 \frac{3}{8} = \frac{8 \times 3 + 3}{8} = \frac{27}{8}$
   • $1 \frac{1}{5} = \frac{5 \times 1 + 1}{5} = \frac{6}{5}$

2. Perform subtraction within the parentheses:

   • $\frac{12}{5} - \frac{51}{8} + \frac{27}{8} = \frac{96}{40} - \frac{255}{40} + \frac{135}{40} = \frac{-24}{40} = -\frac{3}{5}$

3. Perform subtraction outside the parentheses:

   • $\frac{-3}{5} - \frac{29}{30} = \frac{-18}{30} - \frac{29}{30} = \frac{-47}{30}$

4. Divide the first result by the second result:

   • $\frac{\frac{3}{5}}{\frac{-47}{30}} = \frac{3}{5} \times \frac{-30}{47} = \frac{-90}{235} = -\frac{18}{47}$

So, the final result of the expression is $-\frac{18}{47}$.