Question

X + 6 = 6 + х c + 8 = c - 8 а (а - 6) = 0 (у - 4) (у - 9) = 9

Answer 1

1)х+х=12
2х=12
х=6
2)с-с=-8-8
0=-16
3)а^2-6а=0
4)у^2-9у-4у-36=9
у^2-13у=45

Думаю так;)

Answer 2

It seems like you've written down a series of equations. Let's go through them one by one:

1. X + 6 = 6 + X This equation states that the value on the left side (X + 6) is equal to the value on the right side (6 + X). This equation is true for all real values of X. This is an example of an identity, where both sides are equal regardless of the value of X.

2. c + 8 = c - 8 This equation states that the value on the left side (c + 8) is equal to the value on the right side (c - 8). However, if you solve this equation for 'c', you'll realize that it's not possible for these two sides to be equal for any value of 'c'. The solution would be contradictory, which means there is no real solution for 'c' that satisfies this equation.

3. (a - 6) = 0 This equation states that the value inside the parentheses (a - 6) is equal to 0. Solving for 'a', you'll find that 'a' must be equal to 6 for this equation to hold true.

4. (u - 4)(u - 9) = 9 This equation is a quadratic equation in terms of 'u'. Expanding the left side and simplifying the equation, you get: u^2 - 13u + 36 = 9

   Subtracting 9 from both sides: u^2 - 13u + 27 = 0

   This quadratic equation doesn't have simple integer solutions. You can solve it using the quadratic formula or factoring, which might result in two solutions for 'u'.

Remember that solving equations involves finding values for the variables that make the equations true. Sometimes equations have no solutions, sometimes they have unique solutions, and other times they have multiple solutions. If you're trying to solve these equations for specific values of the variables, please provide more context, and I'll be happy to help further.