Question

36*(y-3)=10-2(y+2) 5x+30-2x=42

Answer 1

36*(y-3)=10-2(y-2)
36y-108=10-2y-4
36y+2y=-4+10+108
38y=114
y=114:38
y=3

Answer 2

It seems like you've provided two different equations. Let's solve each equation separately:

Equation 1: $36 \cdot (y - 3) = 10 - 2 \cdot (y + 2)$

First, distribute the terms on the right side: $36y - 108 = 10 - 2y - 4$

Combine like terms: $36y + 2y = 10 + 4 - 108$ $38y = -94$

Now, solve for $y$: $y = \frac{-94}{38} = -\frac{47}{19}$

Equation 2: $5x + 30 - 2x = 42$

Combine like terms: $3x + 30 = 42$

Subtract 30 from both sides: $3x = 12$

Divide by 3: $x = \frac{12}{3} = 4$

So, the solutions are $x = 4$ and $y = -\frac{47}{19}$.