Question

3|х|=12. 5|-х|=3 -|х|+7=10 |-х|:6=2,5

Answer 1

1)3X=12
X=12:3
X=4

2)5X=3
X=3:5
X=0.6

3)X:6=2,5
X=6*2.5
X=15

Answer 2

It looks like you've provided a system of equations involving absolute value expressions. Let's solve each equation step by step:

1. $3|x| = 12$: Divide both sides by 3: $|x| = 4$ This means $x$ can be either 4 or -4.

2. $5|-x| = 3$: Divide both sides by 5: $|-x| = \frac{3}{5}$ Absolute values are non-negative, so there are no solutions for this equation.

3. $-|x| + 7 = 10$: Subtract 7 from both sides: $-|x| = 3$ This doesn't have a real solution, as the absolute value of a number can't be negative.

4. $|-x| : 6 = 2.5$: Multiply both sides by 6: $|-x| = 15$ This means $x$ can be either 15 or -15.

In summary:

• For the first equation, $x$ can be 4 or -4.
• For the second equation, there are no solutions.
• For the third equation, there are no solutions.
• For the fourth equation, $x$ can be 15 or -15.