Question

Tg/1-tg^2a*ctg^2a-1/ctga

Answer 1

1+ tg^2 a = 1/cos^2 a
1+ ctg^2 a = 1/sin^2 a
1/ cos^2 a * sin^2 a/1 = tg^2 a.
tg^2 a = tg^2 a.

Answer 2

To simplify the given expression, let's break it down step by step:

Expression: tg(a) / [1 - tg^2(a) * ctg^2(a)] - [1 / ctg(a)]

Step 1: Simplify the denominator of the first fraction Since 1 - tg^2(a) * ctg^2(a) can be rewritten as 1 - (tg(a) * ctg(a))^2, we can use the trigonometric identity: tg(a) * ctg(a) = 1. Therefore, 1 - (tg(a) * ctg(a))^2 becomes 1 - 1^2 = 1 - 1 = 0.

Expression: tg(a) / [0] - [1 / ctg(a)]

Step 2: Division by 0 is undefined, so the expression is undefined as the first fraction's denominator is 0.

The given expression is undefined.