Question

5*(1+1/5)= 10*(6+3/5)= -2а)- 3b= (a=4/5,b=1/3) 3x(2у-6)- 3у (2x+1) (х=0,3,у = 1,2

Answer 1

5*(1+1/5)=5*6/5=6
10*(6+3/5)=10*33/5=66
-2а- 3b=-2*4/5-3*1/3=-1,6-1=-2,6
(a=4/5,b=1/3)
3x(2у-6)- 3у (2x+1)=6хв-18х-6хв-3у=
-18х-3у=-18*0,3-3*1,2=-5, 4-3,6=-9
(х=0,3,у = 1,2)

Answer 2

Let's solve each of the expressions step by step:

1. 5*(1 + 1/5) = ? First, calculate the value inside the parentheses: 1 + 1/5 = 1 + 0.2 = 1.2 Now, multiply 5 by the result: 5 * 1.2 = 6

So, 5*(1 + 1/5) = 6.

2. 10*(6 + 3/5) = ? First, calculate the value inside the parentheses: 6 + 3/5 = 6 + 0.6 = 6.6 Now, multiply 10 by the result: 10 * 6.6 = 66

So, 10*(6 + 3/5) = 66.

3. -2а) - 3b = (a = 4/5, b = 1/3) = ? Substitute the given values of a and b into the expression: -2*(4/5) - 3*(1/3) = -8/5 - 1 = -8/5 - 5/5 = (-8 - 5) / 5 = -13/5

So, -2а) - 3b = (a = 4/5, b = 1/3) = -13/5.

4. 3x(2у - 6) - 3у(2x + 1) = (x = 0, 3, у = 1, 2) = ? Substitute the given values of x and y into the expression and perform the calculations:

   For (x = 0, y = 1): 3*(21 - 6) - 31*(20 + 1) = 3(-4) - 311 = -12 - 3 = -15

   For (x = 0, y = 2): 3*(22 - 6) - 32*(20 + 1) = 3(-2) - 321 = -6 - 6 = -12

   For (x = 3, y = 1): 3*(21 - 6) - 31*(23 + 1) = 3(-4) - 317 = -12 - 21 = -33

   For (x = 3, y = 2): 3*(22 - 6) - 32*(23 + 1) = 3(-2) - 327 = -6 - 42 = -48

So, the values for the expression for different values of x and y are:

• 3x(2у - 6) - 3у(2x + 1) = (x = 0, 3, y = 1, 2) = -15, -12, -33, -48.