Question

№1 1) -3,48-6,7= -7,34-2,9= 2) 5,4*(-1 1/9)= -1,4*(-2 1/7)= 3) -37,26:(-9,2)= 25,84:(-8,5)= 4) -3,8+4,8*(7 5/6-8 3/4)= (6 7/18-7 1/4)*7,2-2,8= №2 1) 0,4*(4х-0,2)=-4,5-(1,6х-2,5)= 0,3*(5х-0,2)=-2,6-(2,7х-1,4)= 2) (х+0,75):2 1/4=3 1/9:1 3/4= (х-0,5):2 3/4=1 9/11:5/7= №3 1) 5*(0,3а-6)-1,2*(3в-5)= а=-1 1/7 6*(0,4х-3)-4,5*(х+2)= х=1 2/7 №4 1) Дальнобойщик в первый день проехал 2/7 всего пути. Во второй день он проехал 80% пути, пройденного в первый день, а в третий день- оставшиеся 1020км. Сколько километров проехал дальнобойщик во второй день? 2) Дальнобойщик в первый день проехал 40% всего пути. Во второй день он проехал 2/3 пути, пройденного в первый день, а в третий день - оставшиеся 500км. Сколько километров проехал дальнобойщик во второй день? №5 1) Запишите все дроби со знаменателем 19, которые больше 7/9, но меньше 8/9. 2) Запишите все дроби со знаменателем 13, которые больше 5/7, но меньше 6/7. Если вы можете то пожалуйста объясните как это делается, я вас очень прошу.

Answer 1

№1
1) 10.18
10.24
2)6.6
4.2
3)4.05
-3.04
4)-43.4
-103.8

Answer 2

Sure, I'd be happy to help you with these math problems step by step. Let's go through each of them one by one:

№1

1. -3.48 - 6.7 = -10.18
2. -7.34 - (-2.9) = -4.44
3. 5.4 * (-1 1/9) = -6.2 (approx)
4. -1.4 * (-2 1/7) = 3.2 (approx)
5. -37.26 / (-9.2) = 4.05 (approx)
6. 25.84 / (-8.5) = -3.04 (approx)
7. -3.8 + 4.8 * (7 5/6 - 8 3/4) = -5.64 (approx)
8. (6 7/18 - 7 1/4) * 7.2 - 2.8 = -1.22 (approx)

№2

1. 0.4 * (4x - 0.2) = -4.5 - (1.6x - 2.5)
2. 0.3 * (5x - 0.2) = -2.6 - (2.7x - 1.4)
3. (x + 0.75) / 2 1/4 = 3 1/9 / 1 3/4
4. (x - 0.5) / 2 3/4 = 1 9/11 / 5/7

(Note: It seems like there's a formatting issue with the equations in the original question. The equations are not clear, so I can't provide specific answers for the given expressions.)

№3

1. 5 * (0.3a - 6) - 1.2 * (3b - 5) = 0 Solving for 'a,' we get a = -1 1/7

2. 6 * (0.4x - 3) - 4.5 * (x + 2) = 0 Solving for 'x,' we get x = 1 2/7

№4

1. Let's assume the total distance the truck traveled is 'D' km.

   In the first day, the distance traveled = 2/7 * D In the second day, the distance traveled = 80% of (2/7 * D) = 16/100 * 2/7 * D = 32/700 * D In the third day, the distance traveled = 1020 km

   So, we have the equation: 32/700 * D = 1020

   Solving for 'D,' we get D ≈ 22,500 km

   Now, to find the distance traveled in the second day, we calculate: Distance on the second day = 80% of (2/7 * D) ≈ 80% * (2/7 * 22,500) ≈ 3,214.29 km

2. Similarly, let's assume the total distance the truck traveled is 'D' km.

   In the first day, the distance traveled = 40% of D = 2/5 * D In the second day, the distance traveled = 2/3 * (2/5 * D) = 4/15 * D In the third day, the distance traveled = 500 km

   So, we have the equation: 4/15 * D = 500

   Solving for 'D,' we get D = 1875 km

   Now, to find the distance traveled in the second day, we calculate: Distance on the second day = 4/15 * D = 4/15 * 1875 ≈ 500 km

№5

1. To find all fractions with a denominator of 19 between 7/9 and 8/9, we can list them step by step:

   8/19, 9/19, 10/19, 11/19, 12/19, 13/19, 14/19, 15/19, 16/19, 17/19

2. To find all fractions with a denominator of 13 between 5/7 and 6/7, we can list them step by step:

   6/13, 7/13, 8/13, 9/13, 10/13, 11/13

If you have any specific questions or need further explanations for any of the steps, please feel free to ask!