Question

Пасажирский поезд за8 часов прошел 480км а скорый поезд за 6 часов 720 км. Во сколько раз скорость пасажирского поезда меньше скорости скорого поезда

Answer 1

Скорость пассажирского поезда:

v₁ = S₁/t₁ = 480:8 = 60 (км/ч)

Скорость скорого поезда:

v₂ = S₂/t₂ = 720:6 = 120 (км/ч)

Отношение скоростей:

v₂/v₁ = 120:60 = 2

Ответ: Скорость пассажирского поезда в 2 раза меньше скорости скорого.

Answer 2

U=s/t, где U - скорость, s-путь, t- время. По данной формуле находим скорость обоих поездов. Скорость первого равна 60 км/ч, а второго - 120 км/ч
Т.е. U1=1/2U2
Итого: скорость пассажирского поезда меньше в 2 раза.

Answer 3

To find out how many times slower the passenger train is compared to the express train, we need to calculate their respective speeds first.

Speed (or velocity) is calculated by dividing the distance traveled by the time taken to cover that distance.

For the passenger train: Speed of passenger train = Distance traveled by passenger train / Time taken by passenger train Speed of passenger train = 480 km / 8 hours Speed of passenger train = 60 km/h

For the express train: Speed of express train = Distance traveled by express train / Time taken by express train Speed of express train = 720 km / 6 hours Speed of express train = 120 km/h

Now, to find how many times slower the passenger train is compared to the express train, divide the speed of the express train by the speed of the passenger train:

Times slower = Speed of express train / Speed of passenger train Times slower = 120 km/h / 60 km/h Times slower = 2

So, the passenger train is 2 times slower than the express train.