Question

Решите a) x-2/3=1/18 б)19/20-x=1/4в) 1/12+x=3/4+1/6 г)x+3/20=7/10+1/4

Answer 1

Здесь все правильно!
Удачи тебе))

Answer 2

To solve each equation, we will isolate the variable "x" by performing the necessary algebraic operations. Let's solve them one by one:

a) $x - \frac{2}{3} = \frac{1}{18}$

Step 1: Add $\frac{2}{3}$ to both sides to move the constant term to the right side. $x - \frac{2}{3} + \frac{2}{3} = \frac{1}{18} + \frac{2}{3}$

Step 2: Simplify the right side of the equation. $x = \frac{1}{18} + \frac{12}{18}$

Step 3: Combine the fractions on the right side. $x = \frac{13}{18}$

b) $\frac{19}{20} - x = \frac{1}{4}$

Step 1: Subtract $\frac{19}{20}$ from both sides to move the constant term to the left side. $\frac{19}{20} - x - \frac{19}{20} = \frac{1}{4} - \frac{19}{20}$

Step 2: Simplify the left side of the equation. $-x = \frac{1}{4} - \frac{19}{20}$

Step 3: Find a common denominator for the right side. $-x = \frac{5}{20} - \frac{19}{20}$

Step 4: Combine the fractions on the right side. $-x = \frac{-14}{20}$

Step 5: Divide by -1 to isolate x. $x = \frac{14}{20}$

Step 6: Simplify the fraction. $x = \frac{7}{10}$

c) $\frac{1}{12} + x = \frac{3}{4} + \frac{1}{6}$

Step 1: Find a common denominator for the fractions on the right side. $\frac{1}{12} + x = \frac{9}{12} + \frac{2}{12}$

Step 2: Combine the fractions on the right side. $\frac{1}{12} + x = \frac{11}{12}$

Step 3: Subtract $\frac{1}{12}$ from both sides to move the constant term to the right side. $\frac{1}{12} + x - \frac{1}{12} = \frac{11}{12} - \frac{1}{12}$

Step 4: Simplify the left side of the equation. $x = \frac{10}{12}$

Step 5: Simplify the fraction. $x = \frac{5}{6}$

d) $x + \frac{3}{20} = \frac{7}{10} + \frac{1}{4}$

Step 1: Find a common denominator for the fractions on the right side. $x + \frac{3}{20} = \frac{14}{20} + \frac{5}{20}$