Question

9/16-x=1/2 х+2/3=7/8 1/2+x=23/24 x-3/8=1/4 1/4+y=3/7 y-5/12=3/10 y+4/11=3/5 4/15+y=11/25

Answer 1

1/4+y=3/7

У=3/7-1/4

У=12/28-7/28

У=5/28

y-5/12=3/10

У=3/10+5/12

У=8/60+25/60

У=33/60=11/20

y+4/11=3/5

У=3/5-4/11

У=33/55-20/55

У=13/55

4/15+y=11/25

У=11/25-4/15

У=33/75-20/75

У=13/75

Х+2/3=7/8

Х=7/8-2/3

Х=21/24-14/21

Х=7/21=1/3

Х-3/8=1/4

Х=1/4+3/8

Х=2/8+3/8

Х=5/8

9/16-х=1/2

-х=1/2-9/16

-х=8/16-9/16

-х=-1/16

Х=1/16

1/2+х=23/24

Х=23/24-1/2

Х=23/24-12/24

Х=11/24

Answer 2

To solve these equations for the variable x and y, we'll take them one by one. Let's start with the first equation:

1. $\frac{9}{16} - x = \frac{1}{2}$

Step 1: To get rid of the fraction on the left side, we'll subtract $\frac{9}{16}$ from both sides: $x = \frac{9}{16} - \frac{1}{2}$

Step 2: Now, find a common denominator for $\frac{9}{16}$ and $\frac{1}{2}$, which is 16: $x = \frac{9}{16} - \frac{8}{16}$

Step 3: Subtract the fractions: $x = \frac{1}{16}$

So, the solution for the first equation is $x = \frac{1}{16}$.

2. $\frac{1}{2} + x = \frac{23}{24}$

Step 1: To eliminate the fraction on the left side, subtract $\frac{1}{2}$ from both sides: $x = \frac{23}{24} - \frac{1}{2}$

Step 2: Find a common denominator for $\frac{23}{24}$ and $\frac{1}{2}$, which is 24: $x = \frac{23}{24} - \frac{12}{24}$

Step 3: Subtract the fractions: $x = \frac{11}{24}$

So, the solution for the second equation is $x = \frac{11}{24}$.

3. $x - \frac{3}{8} = \frac{1}{4}$

Step 1: To eliminate the fraction on the right side, add $\frac{3}{8}$ to both sides: $x = \frac{1}{4} + \frac{3}{8}$

Step 2: Find a common denominator for $\frac{1}{4}$ and $\frac{3}{8}$, which is 8: $x = \frac{2}{8} + \frac{3}{8}$

Step 3: Add the fractions: $x = \frac{5}{8}$

So, the solution for the third equation is $x = \frac{5}{8}$.

4. $\frac{1}{4} + y = \frac{3}{7}$

Step 1: To eliminate the fraction on the left side, subtract $\frac{1}{4}$ from both sides: $y = \frac{3}{7} - \frac{1}{4}$

Step 2: Find a common denominator for $\frac{3}{7}$ and $\frac{1}{4}$, which is 28: $y = \frac{12}{28} - \frac{7}{28}$

Step 3: Subtract the fractions: $y = \frac{5}{28}$

So, the solution for the fourth equation is $y = \frac{5}{28}$ 0 0