Question

6+...+32 =19 варианты ответов : -17,-29,-43,другой ответ

Answer 1

Другой ответ: -19

Чтобы его получить, нужно сложить 6 и 32(равно 38), 38-19=19 но ответ со знаком минус, так как в левой части большее число, и нужно отрицательное число, чтобы уравнять части

Answer 2

Let's solve the expression 6 + ... + 32 by finding the sum of the numbers in the given range.

We can use the formula for the sum of an arithmetic series:

Sum = (n/2) * (first term + last term)

where n is the number of terms in the series, and the first and last terms are the values at the beginning and end of the series, respectively.

In this case, the first term (a) is 6, the last term (l) is 32, and the number of terms (n) can be calculated by:

n = (last term - first term) / common difference + 1

where the common difference is 1, as we are adding consecutive numbers.

Let's calculate the sum:

n = (32 - 6) / 1 + 1 n = 27

Now, we can find the sum:

Sum = (27/2) * (6 + 32) Sum = 27 * 38 Sum = 1026

Now, let's go through the given answer choices:

1. -17
2. -29
3. -43
4. Another answer

None of the given answer choices match the sum we calculated (1026). Therefore, it seems there might be an issue with the provided answer choices or the initial expression. If you have the correct expression or answer choices, please share them, and I'll be happy to reevaluate.