Question

2 1/6-3/9 плииииз балы дам

Answer 1

$2 \frac{1}{6} - \frac{3}{9} = 2 \frac{3 - 6}{18} = 1 \frac{18 + 3 - 6}{18} = 1 \frac{15}{18} = 1 \frac{5}{6}$

Answer 2

To subtract the two fractions, $\frac{2}{1} + \frac{1}{6}$ and $\frac{3}{9}$, we need to find a common denominator.

Step 1: Find a common denominator The common denominator for $\frac{1}{6}$ and $\frac{3}{9}$ is 6, as both fractions can be expressed with 6 as the denominator.

Step 2: Convert the fractions to have a common denominator $\frac{2}{1} + \frac{1}{6}$ is already in a form with the common denominator 6, so no changes are needed for the first fraction.

To convert $\frac{3}{9}$ to have a denominator of 6, we can multiply both the numerator and denominator by $\frac{6}{9}$ (which is equivalent to multiplying by 1): $\frac{3}{9} \times \frac{6}{9} = \frac{18}{54}$

Now, the expression becomes: $\frac{2}{1} + \frac{18}{54}$.

Step 3: Add the fractions To add the fractions, we need to find a common numerator (the top number) and then write the sum with the common denominator:

$\frac{2}{1} + \frac{18}{54} = \frac{108}{54} + \frac{18}{54} = \frac{126}{54}$.

Step 4: Simplify the fraction The fraction $\frac{126}{54}$ can be simplified by dividing both the numerator and denominator by their greatest common divisor (GCD), which is 18:

$\frac{126}{54} = \frac{7 \times 18}{3 \times 18} = \frac{7}{3}$.

So, $2 \frac{1}{6} - \frac{3}{9} = \frac{7}{3}$ or $2 \frac{1}{6} - \frac{3}{9} = 2\frac{1}{3}$.

Please note that I corrected the mistake in your expression, as $2 \frac{1}{6} - \frac{3}{9}$ should be $2 \frac{1}{6}$ subtracted by $\frac{3}{9}$.