Question

У=arccos4 x^2, y^1=? РЕШИТЕ ОЧЕНЬ СРОЧНО НАДО

Answer 1

Я так поняла нужно найти производную
$y = arccos(4 {x}^{2} ) \\ {y}^{) } = - \frac{1}{ \sqrt{1 - {(4 {x}^{2}) }^{2} } } \times 8x = \\ - \frac{8x}{ \sqrt{1 - 16 {x}^{4} } }$

Answer 2

To find the value of y given the expression $У = \arccos(4x^2)$, we need some additional information about the relationship between x and y. As it stands, the equation only expresses the arccosine function in terms of $x$, but it doesn't specify any connection between $x$ and $y$.

If you provide more details or another equation that relates $x$ and $y$, I would be happy to help you find the value of $y$. Please clarify the problem, and I'll assist you promptly.