Question

(1/3)^2-3х > 81 Поогите плиз)

Answer 1

${( \frac{1}{3} )}^{2} - 3x > 81 \\ \frac{1}{9} - 3x > 81 \\ 1 - 27x > 729 \\ 27x < 728 \\ x < \frac{728}{27} \\ x < 26 \frac{26}{27}$

х принадлежит (-бесконечность;26 26/27)

Answer 2

To solve the inequality, we need to isolate the variable 'x'. Let's go step by step:

Step 1: Simplify the left-hand side of the inequality. (1/3)^2 - 3x > 81

Simplify (1/3)^2: (1/3)^2 = 1/9

The inequality becomes: 1/9 - 3x > 81

Step 2: Combine the constant terms on the left side. 1/9 - 81 > 3x

Step 3: Subtract 1/9 from both sides to isolate '3x'. -81 - 1/9 > 3x

Step 4: Simplify the left side. -729/9 - 1/9 > 3x -730/9 > 3x

Step 5: Divide both sides by 3 to solve for 'x'. -730/9 ÷ 3 > x -730/27 > x

So, the solution to the inequality is: x < -730/27