Question

6-3(х+1)=7-х, 4/9х+14=1/6х+9 .

Answer 1

6-3(х+1)=7-х
6 - 3х - 3 = 7 - х
-3х + х = 7 - 6 + 3
-2х = 4
х = 4 : (-2)
х = -2


4/9х+14=1/6х+9

Если х стоит левее дроби:
(4/9)х+14=(1/6)х+9
4х/9 + 14 = х/6 + 9
4х/9 - х/6 = 9 - 14
2•4х/18 - 3х/18 = -5
8х/18 - 3х/18 = -5
5х/18 = -5
х = -5 • 18/5
х = -18

Если х стоит в знаменателе:
4/(9х) + 14 = 1/(6х) + 9
4/(9х) - 1/(6х) = 9 - 14
2•4/(18х) - 3•1/(18х) = -5
8/(18х) - 3/(18х) = -5
5/(18х) = -5
5/(-5) = 18х
18х = -1
х = -1 : 18
х = -1/18






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Answer 2

6-3(х+1)=7-х

6 - 3х -3 = 7 - х

6 - 3 - 7 = 3х - х

2х = -4

х = -2

Ответ: -2

4/9х+14=1/6х+9

4/9х - 1/6х = 9 - 14

5/18х = -5

х = -18

Ответ: -18

Answer 3

To solve the equations, let's start with each one separately:

1. Equation: 6 - 3(x + 1) = 7 - x

Step 1: Distribute the -3 through the parentheses: 6 - 3x - 3 = 7 - x

Step 2: Combine like terms on both sides of the equation: 3 - 3x = 7 - x

Step 3: Move the x terms to one side of the equation and the constant terms to the other side: -3x + x = 7 - 3

Step 4: Combine like terms again: -2x = 4

Step 5: Solve for x by dividing both sides by -2: x = -4/2 x = -2

So, the solution for the first equation is x = -2.

2. Equation: (4/9)x + 14 = (1/6)x + 9

Step 1: To eliminate fractions, let's multiply the entire equation by the least common multiple (LCM) of 9 and 6, which is 18: 18 * [(4/9)x + 14] = 18 * [(1/6)x + 9]

Step 2: Distribute the 18 on both sides: 4x + 18 * 14 = 3x + 18 * 9

Step 3: Combine like terms on both sides of the equation: 4x + 252 = 3x + 162

Step 4: Move the x terms to one side of the equation and the constant terms to the other side: 4x - 3x = 162 - 252

Step 5: Combine like terms again: x = -90

So, the solution for the second equation is x = -90.