Question

4×(y-3) =16-5 (y+16) 3×(2m+7)+4=5 (m-3)

Answer 1

1) 4у-12=16-5у-80

4у+5у=12+16-80

9у= -52

у= -52/9

у= -5 7/9

2) 6m+21+4=5m-15

6m-5m= -15-21-4

m= -40

Answer 2

To solve the equations, follow these steps:

1. Solve the first equation: 4×(y-3) = 16 - 5(y+16)

Expand and simplify the equation: 4y - 12 = 16 - 5y - 80

Combine like terms: 4y - 5y = 16 - 80 + 12 -y = -52

Divide by -1 to solve for y: y = 52

2. Solve the second equation: 3×(2m+7) + 4 = 5(m-3)

Expand and simplify the equation: 6m + 21 + 4 = 5m - 15

Combine like terms: 6m + 25 = 5m - 15

Subtract 5m from both sides: 6m - 5m + 25 = -15

Combine like terms again: m + 25 = -15

Subtract 25 from both sides to solve for m: m = -15 - 25 m = -40

So, the solutions to the given equations are: y = 52 m = -40