Question

Х²-2х+1=0,.............​

Answer 1

Ответ:1

х²-2х+1=0

по формуле

(х-1)²=0

х=1

Answer 2

To solve the quadratic equation $x^2 - 2x + 1 = 0$, we can use the quadratic formula:

The quadratic formula states that for an equation of the form $ax^2 + bx + c = 0$, the solutions for $x$ can be found using:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

In the equation $x^2 - 2x + 1 = 0$, we have $a = 1$, $b = -2$, and $c = 1$. Now, let's plug these values into the quadratic formula to find the solutions for $x$:

$x = \frac{-(-2) \pm \sqrt{(-2)^2 - 4 \cdot 1 \cdot 1}}{2 \cdot 1}$

$x = \frac{2 \pm \sqrt{4 - 4}}{2}$

$x = \frac{2 \pm \sqrt{0}}{2}$

Since the discriminant (the expression inside the square root) is 0, there is only one real solution for $x$. The $+$ and $-$ in front of the square root don't matter because either way, we get the same value when the square root of 0 is taken.

$x = \frac{2}{2}$

$x = 1$

So, the only solution to the equation $x^2 - 2x + 1 = 0$ is $x = 1$.