
Найдите A U B, A ∩ B, A\B если A=(-5;8) и B=(3:11)


Ответы на вопрос

А U B (-5;11)
A пересечение В (3;8)
знак пересечение не нашла , извините



To find the union (A U B), intersection (A ∩ B), and set difference (A \ B) between sets A and B, we first need to understand the notation used to represent the sets. In the context of your question, A=(-5;8) and B=(3:11) are notations for intervals, not sets. We can rewrite these intervals in set notation to make the operations clearer.
The set A=(-5;8) includes all real numbers greater than -5 and less than 8, but excluding -5 and 8. In set notation, it can be represented as:
A = {x | -5 < x < 8}
Similarly, the set B=(3:11) includes all real numbers greater than 3 and less than 11, excluding 3 and 11:
B = {x | 3 < x < 11}
Now, let's perform the set operations:
- Union (A U B): The union of two sets A and B includes all the elements that are in either A or B or both.
A U B = {x | x ∈ A or x ∈ B}
To find the union, we need to consider all numbers that satisfy the conditions of either A or B:
A U B = {x | -5 < x < 8 or 3 < x < 11}
Since both sets are intervals, we can express the union as a single interval:
A U B = {x | -5 < x < 11}
- Intersection (A ∩ B): The intersection of two sets A and B includes all the elements that are common to both A and B.
A ∩ B = {x | x ∈ A and x ∈ B}
To find the intersection, we need to consider all numbers that satisfy the conditions of both A and B:
A ∩ B = {x | -5 < x < 8 and 3 < x < 11}
Since the sets A and B have no common elements, their intersection is an empty set:
A ∩ B = ∅
- Set Difference (A \ B): The set difference of A and B includes all the elements that are in A but not in B.
A \ B = {x | x ∈ A and x ∉ B}
To find the set difference, we need to consider all numbers that satisfy the condition of A but not B:
A \ B = {x | -5 < x < 8 and (x ≤ 3 or x ≥ 11)}
Since the set B includes all numbers between 3 and 11, excluding 3 and 11 themselves, the set difference A \ B consists of all numbers in the interval (-5, 8) except for the interval (3, 11):
A \ B = {x | -5 < x < 3 or 8 < x < 11}
So, to summarize:
A U B = {x | -5 < x < 11} A ∩ B = ∅ A \ B = {x | -5 < x < 3 or 8 < x < 11}


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