Question

(5x-1)(x+3)-(x-2)(5x-4)-1 при x=2 2/7​

Answer 1

Ответ:

Пошаговое объяснение:

Answer 2

To evaluate the expression (5x-1)(x+3) - (x-2)(5x-4) - 1 at x = 2 2/7, follow these steps:

Step 1: Convert 2 2/7 to an improper fraction. 2 2/7 can be written as (2 * 7 + 2) / 7 = 16/7.

Step 2: Substitute x with 16/7 in the expression. (5 * 16/7 - 1)(16/7 + 3) - (16/7 - 2)(5 * 16/7 - 4) - 1

Step 3: Simplify the expression. (80/7 - 1)(16/7 + 3) - (2/7)(80/7 - 4) - 1 (80/7 - 1)(16/7 + 3) - (160/49) - 1 (80/7 - 1)(16/7 + 3) - (160/49) - 49/49 (80/7 - 1)(16/7 + 3) - (160/49) - (49/49) (80/7 - 1)(16/7 + 3) - (209/49)

Step 4: Further simplify. (80/7 - 7/7)(16/7 + 21/7) - 209/49 (73/7)(37/7) - 209/49 (73 * 37)/(7 * 7) - 209/49 (2701/49) - 209/49 (2701 - 209)/49 2492/49

So, when x = 2 2/7, the expression (5x-1)(x+3) - (x-2)(5x-4) - 1 equals 2492/49.