Question

20(d+1,4)=140 (h-)=*(g-1,2)=5,5*(5x-)=

Answer 1

1)

$20(d + 1.4) = 140$

$d + 1.4 = 7$

$d = 7 - 1.4$

$d = 5.6$

2)

$\frac{1}{6} (h - \frac{4}{7} ) = \frac{2}{3}$

$h = \frac{4}{7} = 4$

$h = 4 + \frac{4}{7}$

$h = \frac{32}{7}$

3)

$1 \frac{1}{3} 4 \times (g - 1.2) = 5.5$

$\frac{4}{3} \times (g - \frac{6}{5} ) = \frac{11}{2}$

$\frac{4}{3} g - \frac{8}{5} = \frac{11}{2}$

$40g - 48 = 165$

$40g = 165 + 48$

$40g = 213$

$g = \frac{213}{40}$

4)

$1 \frac{2}{3} \times (5x - \frac{1}{2} ) = \frac{7}{9}$

$\frac{5}{3} \times (5x - \frac{1}{2} ) = \frac{7}{9}$

$\frac{25}{3} x - \frac{5}{6} = \frac{7}{9}$

$150x - 15 = 14$

$150x = 14 + 15$

$150x = 29$

$x = \frac{29}{150}$



не забудь подписаться)))

Answer 2

It seems like you have provided three mathematical expressions that need to be solved. Let's solve each one step by step:

1. 20(d+1,4) = 140:

It looks like there is a typo or missing information in the first expression. "(d+1,4)" is not a valid mathematical notation, and it's not clear what operation is intended here. Please provide the correct expression, and I'll be happy to help you solve it.

2. (h-) = *(g-1,2) = 5:

This expression is also not standard mathematical notation, and I'm not sure what it means. If you can provide more context or clarify the notation, I'll do my best to assist you further.

3. 5*(5x-) = ?

This expression seems to be missing the right-hand side of the equation. I can help you simplify the left-hand side by removing unnecessary symbols:

5*(5x-) = 25x

If you have a complete equation that includes both sides (left-hand side and right-hand side), please provide it, and I can help you solve it. If you have any other mathematical questions or need further assistance, feel free to ask!