Question

(7x + 2)(x – 2) = 4(x – 2)в квадрате 2.

Answer 1

Ответ:

Пошаговое объяснение:

(7x + 2)(x – 2) = 4(x – 2)²

(7x + 2)(x – 2) - 4(x – 2)²=0

(х-2) ((7x + 2) - 4(x – 2))=0

(х-2) (7x + 2 - 4x + 8)=0

(х-2) (3x + 10)=0

х-2=0     3х+10=0

х=2  х= -10/3

Answer 2

(7x+2)(x-2)=4(x-2)²

(7x+2)(x-2)-4(x-2)²=0

(x-2)(7x+2-4(x-2))=0

(x-2)(7x+2-4x+8)=0

(x-2)(3x+10)=0

x-2=0;x=2

3x+10=0;3x=-10;x=-10/3

otvet -10/3;2

Answer 3

To solve the given equation, let's expand both sides and simplify the expression.

Expanding the left side: (7x + 2)(x - 2) = 7x(x) + 7x(-2) + 2(x) + 2(-2) = 7x^2 - 14x + 2x - 4 = 7x^2 - 12x - 4

Expanding the right side: 4(x - 2)^2 = 4(x - 2)(x - 2) = 4(x(x) - 2x - 2x + 4) = 4(x^2 - 4x + 4) = 4x^2 - 16x + 16

Now, we have the equation: 7x^2 - 12x - 4 = 4x^2 - 16x + 16

To simplify further, we'll move all the terms to one side of the equation: 7x^2 - 4x^2 - 12x + 16x - 4 - 16 = 0

Combining like terms: 3x^2 + 4x - 20 = 0

Now we have a quadratic equation in standard form. To solve it, we can use factoring, completing the square, or the quadratic formula. In this case, let's use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

Here, a = 3, b = 4, and c = -20.

x = (-(4) ± √((4)^2 - 4(3)(-20))) / (2(3)) x = (-4 ± √(16 + 240)) / 6 x = (-4 ± √256) / 6 x = (-4 ± 16) / 6

Simplifying further: x = (-4 + 16) / 6 or x = (-4 - 16) / 6 x = 12 / 6 or x = -20 / 6 x = 2 or x = -10/3

Therefore, the solutions to the equation (7x + 2)(x - 2) = 4(x - 2)^2 are x = 2 and x = -10/3.