Question

1)22√2/13,4+√2=2)33,4√2/13,4+√2=

Answer 1

1) 177корнейиз2/67
2)234корняиз2/67

Answer 2

To solve these expressions, we need to clarify the format of the numbers provided. It seems like you are using a comma (,) as a decimal separator instead of a period (.) commonly used in many regions. Please confirm whether the numbers you provided are meant to be decimals or fractions. If they are decimals, I'll assume the comma is a decimal separator and calculate accordingly.

1. $\frac{22\sqrt{2}}{13.4 + \sqrt{2}}$:

To simplify this expression, we need to rationalize the denominator. To do this, we multiply the numerator and denominator by the conjugate of the denominator, which is $13.4 - \sqrt{2}$:

$$\frac{22\sqrt{2}}{13.4 + \sqrt{2}} \cdot \frac{13.4 - \sqrt{2}}{13.4 - \sqrt{2}} = \frac{22\sqrt{2} \cdot (13.4 - \sqrt{2})}{(13.4)^2 - (\sqrt{2})^2} = \frac{22\sqrt{2} \cdot (13.4 - \sqrt{2})}{179.56 - 2} = \frac{22\sqrt{2} \cdot (13.4 - \sqrt{2})}{177.56}$$

Therefore, the result is approximately $\frac{22\sqrt{2} \cdot (13.4 - \sqrt{2})}{177.56}$.

2. $\frac{33.4\sqrt{2}}{13.4 + \sqrt{2}}$:

Following the same steps as above, we'll rationalize the denominator by multiplying the expression by the conjugate of the denominator, which is $13.4 - \sqrt{2}$:

$$\frac{33.4\sqrt{2}}{13.4 + \sqrt{2}} \cdot \frac{13.4 - \sqrt{2}}{13.4 - \sqrt{2}} = \frac{33.4\sqrt{2} \cdot (13.4 - \sqrt{2})}{(13.4)^2 - (\sqrt{2})^2} = \frac{33.4\sqrt{2} \cdot (13.4 - \sqrt{2})}{179.56 - 2} = \frac{33.4\sqrt{2} \cdot (13.4 - \sqrt{2})}{177.56}$$

Thus, the result is approximately $\frac{33.4\sqrt{2} \cdot (13.4 - \sqrt{2})}{177.56}$