Question

8 3/40 + 12 11/20 + 6 7/80

Answer 1

Ответ:

$8 \frac{3}{40} + 12 \frac{11}{20} + 6 \frac{7}{80} = (8 + 12 + 6) + ( \frac{3}{40} + \frac{11}{20} + \frac{7}{80} ) = 26 + \frac{57}{80} 26 \frac{57}{80}$

Answer 2

To add the mixed numbers, we first need to convert them to improper fractions.

Converting 8 3/40 to an improper fraction: 8 3/40 = (8 * 40 + 3) / 40 = 323/40

Converting 12 11/20 to an improper fraction: 12 11/20 = (12 * 20 + 11) / 20 = 251/20

Converting 6 7/80 to an improper fraction: 6 7/80 = (6 * 80 + 7) / 80 = 487/80

Now, we can add the improper fractions together:

323/40 + 251/20 + 487/80

To add fractions, we need to find a common denominator. In this case, the least common multiple of 40, 20, and 80 is 80. So we'll convert the fractions to have a denominator of 80:

(323/40) * (2/2) = 646/80 (251/20) * (4/4) = 1004/80 (487/80)

Now, we can add the fractions:

646/80 + 1004/80 + 487/80 = (646 + 1004 + 487) / 80 = 2137/80

The sum of the mixed numbers 8 3/40, 12 11/20, and 6 7/80 is 2137/80.