Question

1) (4+2х)*(1-3х)=0 2)(-х-2,5)*(-2х)=0

Answer 1

Ответ:

1) х = -2 или х = 1/3; 2) х = - 2,5 или х = 0.

Пошаговое объяснение:

1) (4 + 2х)*(1 - 3х) = 0

4 + 2х = 0 [1]

или

1 - 3х = 0 [2]

2х = -4 [1]

или

3х = 1 [2]

х = -2 [1]

или

х = 1/3 [2]

2) (- х - 2,5)*(-2х) = 0

- х - 2,5 = 0 [1]

или

- 2х = 0 [2]

х = - 2,5 [1]

или

х = 0 [2]

Answer 2

To solve these equations, we need to find the values of x that make each equation equal to zero. Let's solve them one by one:

1. (4 + 2x) * (1 - 3x) = 0

To find the values of x, we set each factor equal to zero and solve for x:

4 + 2x = 0 or 1 - 3x = 0

Solving the first equation: 4 + 2x = 0 2x = -4 x = -4/2 x = -2

Solving the second equation: 1 - 3x = 0 3x = 1 x = 1/3

So the solutions to the equation (4 + 2x) * (1 - 3x) = 0 are x = -2 and x = 1/3.

2. (-x - 2.5) * (-2x) = 0

Setting each factor equal to zero and solving for x:

-x - 2.5 = 0 or -2x = 0

Solving the first equation: -x - 2.5 = 0 -x = 2.5 x = -2.5

Solving the second equation: -2x = 0 x = 0

So the solutions to the equation (-x - 2.5) * (-2x) = 0 are x = -2.5 and x = 0.

Therefore, the solutions for each equation are:

1. (4 + 2x) * (1 - 3x) = 0: x = -2, x = 1/3
2. (-x - 2.5) * (-2x) = 0: x = -2.5, x = 0