Question

2) (3,5 – x)(7x+ 2) + (3,5x - 1)(7 + 2x) = -450

Answer 1

(24,5x+7-7x^2-2x)+(24,5x+7x-7-2x)
49x+3x-7x^2=-450
-7x^2+52x+450=0
7x^2-52x-450=0
D=2704+12600=...
X1,2=52+-123/14=
X1=12
X2=-5

Answer 2

To solve the equation (3.5 - x)(7x + 2) + (3.5x - 1)(7 + 2x) = -450, we will expand and simplify the expression and then solve for x.

Expanding the equation:

(3.5 - x)(7x + 2) + (3.5x - 1)(7 + 2x) = -450

Expanding the first term:

(3.5)(7x) + (3.5)(2) - x(7x) - x(2) + (3.5x)(7) + (3.5x)(2) - 1(7) - 1(2x) = -450

24.5x + 7 - 7x^2 - 2x + 24.5x + 7x - 7 - 2x = -450

Combining like terms:

24.5x + 24.5x - 7x^2 + 7x - 2x - 2x + 7 - 7 - 450 = 0

49x + 3x - 7x^2 - 443 = 0

52x - 7x^2 - 443 = 0

Now we have a quadratic equation. To solve for x, we can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

In this case, a = -7, b = 52, and c = -443. Substituting these values into the formula:

x = (-52 ± √(52^2 - 4(-7)(-443))) / (2(-7))

Simplifying further:

x = (-52 ± √(2704 - 12388)) / (-14)

x = (-52 ± √(-9684)) / (-14)

Since the value inside the square root is negative, this equation has no real solutions. Therefore, there are no real values of x that satisfy the equation (3.5 - x)(7x + 2) + (3.5x - 1)(7 + 2x) = -450.