Question

10.a) 4(x+2)=326) 2(x+3)=12​

Answer 1

4(х+2) =32
4х +8 =32
4х = 32-8
4х = 24
х = 24 : 4
х = 6



2(х+3) =12
2х+6 = 12
2х = 12-6
2х=6
х= 6:2
х=3

Answer 2

To solve these equations, we need to isolate the variable "x." Let's go through each one step by step:

10.a) 4(x + 2) = 32

Step 1: Distribute the 4 on the left side of the equation. 4 * x + 4 * 2 = 32 4x + 8 = 32

Step 2: Move the constant term (8) to the right side by subtracting it from both sides. 4x = 32 - 8 4x = 24

Step 3: Now, divide both sides by 4 to solve for x. x = 24 / 4 x = 6

So, the solution for the equation is x = 6.

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10.b) 2(x + 3) = 12

Step 1: Distribute the 2 on the left side of the equation. 2 * x + 2 * 3 = 12 2x + 6 = 12

Step 2: Move the constant term (6) to the right side by subtracting it from both sides. 2x = 12 - 6 2x = 6

Step 3: Now, divide both sides by 2 to solve for x. x = 6 / 2 x = 3

So, the solution for the equation is x = 3.