Question

A3+a4+a5+a6=64, a3+a6=252

Answer 1

Ответ:

1)3*3+3*4+3*5+3*6=54

2)29*3+29*6=252

Answer 2

To solve this system of equations, we'll use the given information to find the values of the variables. Let's proceed step by step:

1. The first equation: A3 + A4 + A5 + A6 = 64
2. The second equation: A3 + A6 = 252

We can see that both equations contain A3 and A6. So, let's isolate A3 and A6 from the second equation:

A3 = 252 - A6 ....(Equation 3)

Now, we have an expression for A3 in terms of A6. Let's substitute this value of A3 into the first equation:

(252 - A6) + A4 + A5 + A6 = 64

Now, we can simplify this equation:

252 + A4 + A5 = 64 A4 + A5 = 64 - 252 A4 + A5 = -188 ....(Equation 4)

We have another equation (Equation 4) that relates A4 and A5. However, without additional information or equations, we cannot find specific values for A4 and A5. The system is underdetermined, meaning there are multiple possible solutions for A4 and A5.

We can, however, find the values of A3 and A6 using Equation 3:

A3 = 252 - A6

And since we don't have a specific value for A6, we can express A3 in terms of A6. Any value of A6 will give us the corresponding value of A3 using the equation above.