Question

4×|2x-5|=28 ??????????5​

Answer 1

Пошаговое объяснение:

если конечно там такие скобки,а не круглые

Answer 2

1 способ

4×|2х-5|=4×(2х+5)=8х+20=28

8х=8

Х=1

Answer 3

To solve the equation 4×|2x-5|=28, we can start by dividing both sides of the equation by 4 to simplify it:

|2x-5| = 7

Now, we have an absolute value equation. To solve it, we need to consider two cases: one when the expression inside the absolute value is positive and one when it is negative.

Case 1: 2x - 5 is positive (2x - 5 > 0) In this case, we can remove the absolute value notation and write the equation as:

2x - 5 = 7

Adding 5 to both sides, we get:

2x = 12

Dividing both sides by 2, we find:

x = 6

So, x = 6 is one possible solution.

Case 2: 2x - 5 is negative (2x - 5 < 0) In this case, the expression inside the absolute value becomes its negation. Therefore, we have:

-(2x - 5) = 7

Expanding the negative sign, we get:

-2x + 5 = 7

Subtracting 5 from both sides, we have:

-2x = 2

Dividing both sides by -2 (and flipping the inequality sign since we divided by a negative number), we find:

x = -1

So, x = -1 is the other possible solution.

Therefore, the equation 4×|2x-5|=28 has two solutions: x = 6 and x = -1.