Question

Y=-x^2 -5x+4 найдите (К;-2)​

Answer 1

у=-x² -5x+4 найдите к, если график проходит через точку (к;-2)​

4=-к²-5к+4

-к²-5к=0. откуда к=0 или к=5

Answer 2

To find the value of Y at the point (K, -2) in the given equation Y = -x^2 - 5x + 4, you need to substitute the value of x with K and then calculate the corresponding Y value.

Let's do that:

Y = -x^2 - 5x + 4

Now, we'll substitute x with K:

Y = -(K)^2 - 5(K) + 4

Now, calculate the value of Y:

Y = -(K)^2 - 5(K) + 4 Y = -(K^2) - 5K + 4

So, at the point (K, -2), the value of Y is given by the expression -(K^2) - 5K + 4.