Question

10-x:6≥x+7:5 Решите пж

Answer 1

Пошаговое объяснение:

1) Сократить дробь. Выполнить деление:

$10 - \frac{1}{6} x \geqslant x + 1.4$

2) Преобразовать десятичную дробь в обыкновенную:

$10 - \frac{1}{6} x \geqslant x + \frac{7}{5}$

3) Умножить обе части уравнения на 30:

$300 - 5x \geqslant 30x + 42$

4) Перенести слагаемое в другую часть уравнения:

$- 5x - 30x \geqslant 42 - 300$

5) Привести подобные члены. Вычислить:

$- 35x \geqslant - 258$

6) Разделить обе части уравнения на -35:

$x \leqslant \frac{258}{35}$

Answer 2

To solve the inequality, we need to find the value of x that satisfies the given inequality:

$\frac{10-x}{6} \geq \frac{x+7}{5}$

To eliminate the fractions, we can multiply both sides of the inequality by the least common multiple (LCM) of 6 and 5, which is 30. Multiplying both sides by 30 gives:

$30 \cdot \frac{10-x}{6} \geq 30 \cdot \frac{x+7}{5}$

Simplify both sides:

$5(10 - x) \geq 6(x + 7)$

Now distribute the multiplication:

$50 - 5x \geq 6x + 42$

Next, let's isolate the x terms on one side of the inequality and the constants on the other side. To do this, we'll subtract 6x from both sides:

$50 - 5x - 6x \geq 42$

Simplify:

$50 - 11x \geq 42$

Now, subtract 50 from both sides to isolate the term with x:

$-11x \geq 42 - 50$

Simplify:

$-11x \geq -8$

Finally, divide both sides by -11. Note that since we're dividing by a negative number, the inequality sign flips:

$x \leq \frac{-8}{-11}$

Simplify the right side:

$x \leq \frac{8}{11}$

So, the solution to the inequality is:

$x \leq \frac{8}{11}$