Question

B) 3x2 - 98x + 5 = 0

Answer 1

Ответ:

Пошаговое объяснение:

3x²-98x+5=0; D=9604-60=9544

x₁=(98-√9544)/6=(98-2√2386)/6=(49-√2386)/3

x₂=(98+√9544)/6=(√2386 +49)/3

Ответ: (49-√2386)/3 и (√2386 +49)/3.

Answer 2

To solve the quadratic equation 3x^2 - 98x + 5 = 0, we can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

In this case, a = 3, b = -98, and c = 5. Substituting these values into the quadratic formula, we get:

x = (-(-98) ± √((-98)^2 - 4 * 3 * 5)) / (2 * 3) = (98 ± √(9604 - 60)) / 6 = (98 ± √(9544)) / 6 = (98 ± 97.692) / 6

Therefore, the solutions to the quadratic equation 3x^2 - 98x + 5 = 0 are:

x = (98 + 97.692) / 6 ≈ 32.949

x = (98 - 97.692) / 6 ≈ 0.051

So the approximate solutions are x ≈ 32.949 and x ≈ 0.051.