Question

Tg (вквадрате) 6x-3=o

Answer 1

Ответ:

$\tan {}^{2} (6x - 3) = 0 \\ \tan(6x - 3) = 0 \\ 6x - 3 = \arctan(0) + \pi \times n \\6x = 3 + \pi \times n \\ x = \frac{1}{2} + \frac{\pi \times n}{6}$

n є Z(целым числам)

Answer 2

To solve the equation t^2 - 6x - 3 = 0, we can use the quadratic formula. The quadratic formula states that for an equation of the form ax^2 + bx + c = 0, the solutions for x can be found using the formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

In our case, a = 1, b = -6, and c = -3. Substituting these values into the quadratic formula, we have:

x = (-(-6) ± √((-6)^2 - 4(1)(-3))) / (2(1)) x = (6 ± √(36 + 12)) / 2 x = (6 ± √48) / 2 x = (6 ± 4√3) / 2 x = 3 ± 2√3

Therefore, the solutions to the equation t^2 - 6x - 3 = 0 are x = 3 + 2√3 and x = 3 - 2√3.