Question

21x^2-5x+1=0 pleaseeee​

Answer 1

Ответ:

21х²-5х+1=0

D=b²-4ac=(-5)²-4•21•1=25-84=-59

D<0, поэтому уравнение не имеет решений.

Answer 2

Ответ: дискриминант 25-4*21<0, уравнение не имеет корней.

Пошаговое объяснение:

Answer 3

The equation you've provided is a quadratic equation in the form of $ax^2 + bx + c = 0$, where $a = 21$, $b = -5$, and $c = 1$. To solve for the value(s) of $x$, you can use the quadratic formula:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

Plugging in the values from your equation:

$x = \frac{-(-5) \pm \sqrt{(-5)^2 - 4 \cdot 21 \cdot 1}}{2 \cdot 21}$

Simplifying the equation under the square root:

$x = \frac{5 \pm \sqrt{25 - 84}}{42}$ $x = \frac{5 \pm \sqrt{-59}}{42}$

Since the square root of a negative number is an imaginary number, the solutions will be complex:

$x = \frac{5 \pm i\sqrt{59}}{42}$

So, the solutions for the equation $21x^2 - 5x + 1 = 0$ are:

$x = \frac{5 + i\sqrt{59}}{42} \quad \text{and} \quad x = \frac{5 - i\sqrt{59}}{42}$