Question

A^2+bc-b^2-ac/ab-c^2-ac+b^2 упростите выражение и решите​

Answer 1

$\dfrac{a^2+bc-b^2-ac}{ab-c^2-ac+b^2}=\dfrac{(a-b)(a+b)-c(a-b)}{a(b-c)-(b-c)(b+c)}=\dfrac{(a-b)(a+b-c)}{(b-c)(a-b-c)}$

Выражение не упростить.

Answer 2

To simplify the expression A^2 + (bc - b^2 - ac) / (ab - c^2 - ac + b^2), we can first factor the denominator and then combine like terms.

The denominator can be factored as follows: ab - c^2 - ac + b^2 = ab + b^2 - ac - c^2 = b(a + b) - c(a + b) = (a + b)(b - c)

Now, the expression becomes: A^2 + (bc - b^2 - ac) / (a + b)(b - c)

Next, let's factor out the common factor (b - c) from the numerator (bc - b^2 - ac): bc - b^2 - ac = b(c - b) - a(c - b) = (c - b)(b - a)

Now the expression becomes: A^2 + (c - b)(b - a) / (a + b)(b - c)

At this point, we can see that the (b - a) in the numerator and (a + b) in the denominator can be canceled out:

A^2 + (c - b) / (b - c)

Now, the expression is simplified, and we cannot simplify it further without knowing the specific values of A, b, and c.

If you have specific numerical values for A, b, and c, you can substitute them into the expression to find the result. Otherwise, the expression remains as A^2 + (c - b) / (b - c).