Question

-3-3(3-2x)=1 ...........................

Answer 1

$\displaystyle \tt -3-3(3-2x)=1\\\displaystyle \tt -3-3\cdot3-3\cdot(-2x)=1\\\displaystyle \tt -3-9+6x=1\\\displaystyle \tt -12+6x=1\\\displaystyle \tt 6x=1+12\\\displaystyle \tt 6x=13\\\displaystyle \tt x=13\div6\\\\ \displaystyle \tt \bold{x=2\frac{1}{6}}$

Answer 2

To solve the equation -3 - 3(3 - 2x) = 1, follow these steps:

Step 1: Distribute the -3 on the left side of the equation: -3 - 3(3 - 2x) = 1 -3 - 9 + 6x = 1

Step 2: Combine like terms on the left side of the equation: 6x - 12 = 1

Step 3: Move the constant term to the right side of the equation by adding 12 to both sides: 6x = 1 + 12 6x = 13

Step 4: Isolate x by dividing both sides by 6: x = 13/6

So the solution to the equation is x = 13/6.