Question

Y(2y-1)(2y-2)-4y(y+1)^+2y(7y+1)

Answer 1

Ответ:

$y(2y-1)(2y-2)-4y(y+1)^2+y(7y+1) = y(4y^2-4y-2y+2) - 4y(y^2+2y+1) +\\\\ 7y^2+7y = 4y^3 - 6y^2 + 2y - 4y^3-8y^2-4y+7y^2+y = -7y^2- y = -y(7y+1)$

Answer 2

Let's simplify the expression step by step:

1. Start by distributing the terms within the parentheses: Y(2y-1)(2y-2) - 4y(y+1) + 2y(7y+1)

2. Now, perform multiplication within each set of parentheses: Y(4y^2 - 4y - 2y + 2) - 4y(y+1) + 2y(7y+1)

3. Simplify the expressions within the parentheses: Y(4y^2 - 6y + 2) - 4y(y+1) + 2y(7y+1)

4. Distribute the Y to the terms within the first set of parentheses: 4y^3 - 6y^2 + 2y - 4y(y+1) + 2y(7y+1)

5. Continue simplifying the expression: 4y^3 - 6y^2 + 2y - 4y^2 - 4y + 2y(7y+1)

6. Combine like terms: 4y^3 - (6y^2 + 4y^2) + (2y - 4y) + 2y(7y+1)

7. Simplify further: 4y^3 - 10y^2 - 2y + 2y(7y+1)

8. Distribute the 2y to the terms within the parentheses: 4y^3 - 10y^2 - 2y + 14y^2 + 2y

9. Combine like terms: 4y^3 + (14y^2 - 10y^2) + (-2y + 2y)

10. Simplify the expression: 4y^3 + 4y^2

So, the simplified expression is: 4y^3 + 4y^2.