Question

13 х - 4у = 8- 3x+y=1​

Answer 1

Пошаговое объяснение: я делаю так

1) 13х-4у=8

-3х+у=1 это все умножаем на 4 т.е/*4

2) Объединяем и получаем х=12

Т.к. у-ки взаимо отнимаются и получают 0у

3) подставляем х= 12 в одно из уравнений и получаем:

(-36)+у=1

у=37 т.е. 36+1

Ответ: х= 12 у=37

Answer 2

Ответ:

х=12 у=36

вроде так

Пошаговое объяснение:

не уверенна

Answer 3

It looks like you've provided a system of two linear equations with two variables, x and y. The system of equations is as follows:

1. 13x - 4y = 8
2. -3x + y = 1

To solve this system of equations, we can use various methods such as substitution, elimination, or matrices. Let's use the elimination method in this case.

First, let's multiply the second equation by 4 to make the coefficients of y in both equations equal:

Original equations:

1. 13x - 4y = 8
2. -3x + y = 1

Multiplying the second equation by 4: 2'. -12x + 4y = 4

Now we can add equation 1 and equation 2' to eliminate y:

(13x - 4y) + (-12x + 4y) = 8 + 4 1x = 12 x = 12

Now that we have the value of x, we can substitute it back into the second equation to solve for y:

-3x + y = 1 -3(12) + y = 1 -36 + y = 1 y = 1 + 36 y = 37

So, the solution to the system of equations is x = 12 and y = 37.